2+5b=2b^2

Solution for 2+5b=2b^2 equation:

2+5b=2b^2

We move all terms to the left:

2+5b-(2b^2)=0

determiningTheFunctionDomain
-2b^2+5b+2=0

a = -2; b = 5; c = +2;
Δ = b2-4ac
Δ = 52-4·(-2)·2
Δ = 41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{41}}{2*-2}=\frac{-5-\sqrt{41}}{-4}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{41}}{2*-2}=\frac{-5+\sqrt{41}}{-4}
$